JavaScript-Developer-I Exam Dumps : Salesforce Certified JavaScript Developer (JS-Dev-101)

Evaluate each option:

A. Arguments for .then() are optional.

This is correct.

then() has the signature:

promise.then(onFulfilled?, onRejected?)

Both arguments (onFulfilled and onRejected) are optional.

If a callback is not supplied, JavaScript provides a default pass-through handler.

B. .then() cannot be added after a catch.

Incorrect.

Promises support chaining in any order:

promise

catch(...)

then(...);

After a catch, the chain continues normally.

C. .then() manipulates and returns the original promise.

Incorrect.

then() always returns a new promise , not the original one.

This is fundamental to promise chaining behavior.

D. Returning values in .then() is not necessary.

Incorrect.

If you want the next .then() in the chain to receive a value, the current .then() must explicitly return it:

then(value = > {

return value * 2; // passes to next .then()

})

If nothing is returned, the next .then() receives undefined.

Why A is correct

It is the only statement that accurately describes built-in Promise behavior:

then() accepts optional arguments.

JavaScript Knowledge References (text-only)

.then(onFulfilled?, onRejected?) accepts optional handlers.

Promise chaining creates new promises for each .then().

catch() can be followed by additional .then() calls.

Returning inside .then() passes values to the next step in the chain.

The key line is:

for (let something of obj) {

In JavaScript:

for...of is used to iterate over iterable objects, such as:

Arrays

Strings

Maps

Sets

Other objects that implement a [Symbol.iterator] method.

Plain JavaScript objects created with object literal {} are not iterable by default . They do not have [Symbol.iterator], so using for...of directly on them causes a runtime error.

Specifically:

for (let something of obj) { ... }

will throw a TypeError similar to:

obj is not iterable

Therefore, the loop body never executes, and console.log(output); is never reached without an error.

Why other options are incorrect:

B. [1, 2]

To get [1, 2], you could use Object.values(obj) and iterate that array.

But here, for...of obj never yields values because it throws an error.

C. [ " foo " , " bar " ]

To get property names, you could use Object.keys(obj) with for...of.

Again, the code does not do that; it incorrectly tries to iterate the object directly.

D. [ " foo:1 " , " bar:2 " ]

You would need both keys and values, combining them manually.

The given code does not implement such logic and fails before pushing anything into output.

Hence, the correct answer is:

Answer: A

Study Guide / Concept References (no links):

Difference between for...of and for...in

Iterables in JavaScript and [Symbol.iterator]

Plain objects {} are not iterable by default

Correct patterns to iterate object keys/values (Object.keys, Object.values, Object.entries)

The correct answer is C .

When getAvailability(item) returns true, the code inside the if block executes:

var msg = " Username available " ;

return msg;

The variable msg receives the string value:

" Username available "

Then that same value is returned from the function.

The key point is that var is function-scoped, not block-scoped. So msg belongs to the function scope of getAvailabilityMessage(). However, because the return msg; statement is inside the same if block, the function immediately returns the assigned string when the username is available.

Option A is incorrect because msg is defined before it is returned.

Option B is incorrect because " newUserName " is not assigned or returned anywhere in the function.

Option D would only happen if getAvailability(item) returned false, because then the function would finish without an explicit return value.

For the available username scenario, the verified answer is C .