Big 11.11 Sale 70% Discount Offer - Ends in 0d 00h 00m 00s - Coupon code: save70

1D0-541 Exam Dumps : CIW v5 Database Design Specialist

PDF
1D0-541 pdf
 Real Exam Questions and Answer
 Last Update: Nov 12, 2025
 Question and Answers: 124
 Compatible with all Devices
 Printable Format
 100% Pass Guaranteed
$25.5  $84.99
1D0-541 exam
PDF + Testing Engine
1D0-541 PDF + engine
 Both PDF & Practice Software
 Last Update: Nov 12, 2025
 Question and Answers: 124
 Discount Offer
 Download Free Demo
 24/7 Customer Support
$40.5  $134.99
Testing Engine
1D0-541 Engine
 Desktop Based Application
 Last Update: Nov 12, 2025
 Question and Answers: 124
 Create Multiple Test Sets
 Questions Regularly Updated
  90 Days Free Updates
  Windows and Mac Compatible
$30  $99.99

Verified By IT Certified Experts

CertsTopics.com Certified Safe Files

Up-To-Date Exam Study Material

99.5% High Success Pass Rate

100% Accurate Answers

Instant Downloads

Exam Questions And Answers PDF

Try Demo Before You Buy

Certification Exams with Helpful Questions And Answers

CIW v5 Database Design Specialist Questions and Answers

Question 1

In which phase of database design do you identify entities, attribute domains, and relationships?

Options:

A.

Logical

B.

Physical

C.

Application

D.

Conceptual

Buy Now
Question 2

Consider the relations shown in the exhibit. Due to restructuring, the sales department has been eliminated and the employees working in that department have been dismissed. All ID information is stored as integers. Which SQL statement would be used to return a relation with all information for the employees who have been dismissed?

Options:

A.

SELECT *

FROM Employee;

B.

SELECT ID, Last_Name

FROM Employee;

WHERE ID = 0004;

C.

SELECT *

FROM Employee

WHERE Dept_ID = 022;

D.

SELECT *

FROM Employee

WHERE Dept_ID = 022;

Question 3

What is the highest normal form of the relation(s) shown in the exhibit?

Options:

A.

Second normal form

B.

First normal form

C.

Boyce-Codd normal form

D.

Third normal form

E.

STUDENT( Student_Number: integer NOT NULL Name:

variable length character string length 20 NOT NULL)

Primary Key Student_Number CLASS( Class_Num: integer

NOT NULL Class_Name: integer NOT NULL) Primary Key

Class_Num

F.

STUDENT( Student_Number: integer NOT NULL Name:

variable length character string length 20 NOT NULL)

Primary Key Student_Number CLASS( Class_Num: integer

NOT NULL Class_Name: integer NOT NULL) Primary Key

Class_Num Foreign Key Class_Num References STUDENT

G.

STUDENT( Student_Number: integer NOT NULL Name:

variable length character string length 20 NOT NULL)

Primary Key StudenMMumber STU_CLASS(

Student_Number: integer NOT NULL Class_Num: integer

NOT NULL) Primary Key Student_Number CLASS(

Class_Num: integer NOT NULL Class_Name: integer NOT

NULL) Primary Key Class_Num