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Snowflake ARA-C01 Exam With Confidence Using Practice Dumps

Exam Code:
ARA-C01
Exam Name:
SnowPro Advanced: Architect Certification Exam
Vendor:
Questions:
182
Last Updated:
May 10, 2026
Exam Status:
Stable
Snowflake ARA-C01

ARA-C01: SnowPro Advanced: Architect Exam 2025 Study Guide Pdf and Test Engine

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SnowPro Advanced: Architect Certification Exam Questions and Answers

Question 1

An Architect needs to automate the daily Import of two files from an external stage into Snowflake. One file has Parquet-formatted data, the other has CSV-formatted data.

How should the data be joined and aggregated to produce a final result set?

Options:

A.

Use Snowpipe to ingest the two files, then create a materialized view to produce the final result set.

B.

Create a task using Snowflake scripting that will import the files, and then call a User-Defined Function (UDF) to produce the final result set.

C.

Create a JavaScript stored procedure to read. join, and aggregate the data directly from the external stage, and then store the results in a table.

D.

Create a materialized view to read, Join, and aggregate the data directly from the external stage, and use the view to produce the final result set

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Question 2

An Architect has a table called leader_follower that contains a single column named JSON. The table has one row with the following structure:

{

"activities": [

{ "activityNumber": 1, "winner": 5 },

{ "activityNumber": 2, "winner": 4 }

],

"follower": {

"name": { "default": "Matt" },

"number": 4

},

"leader": {

"name": { "default": "Adam" },

"number": 5

}

}

Which query will produce the following results?

ACTIVITY_NUMBER

WINNER_NAME

1

Adam

2

Matt

Options:

A.

SELECT lf.json:activities.activityNumber AS activity_number,

IFF(

lf.json:activities.activityNumber = lf.json:leader.number,

lf.json:leader.name.default,

lf.json:follower.name.default

)::VARCHAR

FROM leader_follower lf;

B.

SELECT

C.

value:activityNumber AS activity_number,

IFF(

D.

value:winner = lf.json:leader.number,

lf.json:leader.name.default,

lf.json:follower.name.default

)::VARCHAR AS winner_name

FROM leader_follower lf,

LATERAL FLATTEN(input => json:activities) p;

E.

SELECT

F.

value:activityNumber AS activity_number,

IFF(

G.

value:winner = lf.json:leader.number,

lf.json:leader,

lf.json:follower

)::VARCHAR AS winner_name

FROM leader_follower lf,

LATERAL FLATTEN(input => json:activities) p;

Question 3

What step will im the performance of queries executed against an external table?

Options:

A.

Partition the external table.

B.

Shorten the names of the source files.

C.

Convert the source files' character encoding to UTF-8.

D.

Use an internal stage instead of an external stage to store the source files.