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Snowflake ARA-C01 Exam With Confidence Using Practice Dumps

Exam Code:
ARA-C01
Exam Name:
SnowPro Advanced: Architect Certification Exam
Vendor:
Questions:
182
Last Updated:
Feb 14, 2026
Exam Status:
Stable
Snowflake ARA-C01

ARA-C01: SnowPro Advanced: Architect Exam 2025 Study Guide Pdf and Test Engine

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SnowPro Advanced: Architect Certification Exam Questions and Answers

Question 1

What does a Snowflake Architect need to consider when implementing a Snowflake Connector for Kafka?

Options:

A.

Every Kafka message is in JSON or Avro format.

B.

The default retention time for Kafka topics is 14 days.

C.

The Kafka connector supports key pair authentication, OAUTH. and basic authentication (for example, username and password).

D.

The Kafka connector will create one table and one pipe to ingest data for each topic. If the connector cannot create the table or the pipe it will result in an exception.

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Question 2

An Architect needs to design a data unloading strategy for Snowflake, that will be used with the COPY INTO command.

Which configuration is valid?

Options:

A.

Location of files: Snowflake internal location. File formats: CSV, XML. File encoding: UTF-8. Encryption: 128-bit

B.

Location of files: Amazon S3. File formats: CSV, JSON. File encoding: Latin-1 (ISO-8859). Encryption: 128-bit

C.

Location of files: Google Cloud Storage. File formats: Parquet. File encoding: UTF-8· Compression: gzip

D.

Location of files: Azure ADLS. File formats: JSON, XML, Avro, Parquet, ORC. Compression: bzip2. Encryption: User-supplied key

Question 3

An Architect has a table called leader_follower that contains a single column named JSON. The table has one row with the following structure:

{

"activities": [

{ "activityNumber": 1, "winner": 5 },

{ "activityNumber": 2, "winner": 4 }

],

"follower": {

"name": { "default": "Matt" },

"number": 4

},

"leader": {

"name": { "default": "Adam" },

"number": 5

}

}

Which query will produce the following results?

ACTIVITY_NUMBER

WINNER_NAME

1

Adam

2

Matt

Options:

A.

SELECT lf.json:activities.activityNumber AS activity_number,

IFF(

lf.json:activities.activityNumber = lf.json:leader.number,

lf.json:leader.name.default,

lf.json:follower.name.default

)::VARCHAR

FROM leader_follower lf;

B.

SELECT

C.

value:activityNumber AS activity_number,

IFF(

D.

value:winner = lf.json:leader.number,

lf.json:leader.name.default,

lf.json:follower.name.default

)::VARCHAR AS winner_name

FROM leader_follower lf,

LATERAL FLATTEN(input => json:activities) p;

E.

SELECT

F.

value:activityNumber AS activity_number,

IFF(

G.

value:winner = lf.json:leader.number,

lf.json:leader,

lf.json:follower

)::VARCHAR AS winner_name

FROM leader_follower lf,

LATERAL FLATTEN(input => json:activities) p;