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Snowflake ARA-C01 Exam With Confidence Using Practice Dumps

Exam Code:
ARA-C01
Exam Name:
SnowPro Advanced: Architect Certification Exam
Vendor:
Questions:
182
Last Updated:
Feb 8, 2026
Exam Status:
Stable
Snowflake ARA-C01

ARA-C01: SnowPro Advanced: Architect Exam 2025 Study Guide Pdf and Test Engine

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SnowPro Advanced: Architect Certification Exam Questions and Answers

Question 1

An Architect has a table called leader_follower that contains a single column named JSON. The table has one row with the following structure:

{

"activities": [

{ "activityNumber": 1, "winner": 5 },

{ "activityNumber": 2, "winner": 4 }

],

"follower": {

"name": { "default": "Matt" },

"number": 4

},

"leader": {

"name": { "default": "Adam" },

"number": 5

}

}

Which query will produce the following results?

ACTIVITY_NUMBER

WINNER_NAME

1

Adam

2

Matt

Options:

A.

SELECT lf.json:activities.activityNumber AS activity_number,

IFF(

lf.json:activities.activityNumber = lf.json:leader.number,

lf.json:leader.name.default,

lf.json:follower.name.default

)::VARCHAR

FROM leader_follower lf;

B.

SELECT

C.

value:activityNumber AS activity_number,

IFF(

D.

value:winner = lf.json:leader.number,

lf.json:leader.name.default,

lf.json:follower.name.default

)::VARCHAR AS winner_name

FROM leader_follower lf,

LATERAL FLATTEN(input => json:activities) p;

E.

SELECT

F.

value:activityNumber AS activity_number,

IFF(

G.

value:winner = lf.json:leader.number,

lf.json:leader,

lf.json:follower

)::VARCHAR AS winner_name

FROM leader_follower lf,

LATERAL FLATTEN(input => json:activities) p;

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Question 2

A table contains five columns and it has millions of records. The cardinality distribution of the columns is shown below:

Column C4 and C5 are mostly used by SELECT queries in the GROUP BY and ORDER BY clauses. Whereas columns C1, C2 and C3 are heavily used in filter and join conditions of SELECT queries.

The Architect must design a clustering key for this table to improve the query performance.

Based on Snowflake recommendations, how should the clustering key columns be ordered while defining the multi-column clustering key?

Options:

A.

C5, C4, C2

B.

C3, C4, C5

C.

C1, C3, C2

D.

C2, C1, C3

Question 3

A Snowflake Architect is setting up database replication to support a disaster recovery plan. The primary database has external tables.

How should the database be replicated?

Options:

A.

Create a clone of the primary database then replicate the database.

B.

Move the external tables to a database that is not replicated, then replicate the primary database.

C.

Replicate the database ensuring the replicated database is in the same region as the external tables.

D.

Share the primary database with an account in the same region that the database will be replicated to.