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Snowflake ARA-C01 Exam With Confidence Using Practice Dumps

Exam Code:
ARA-C01
Exam Name:
SnowPro Advanced: Architect Certification Exam
Vendor:
Questions:
182
Last Updated:
May 6, 2026
Exam Status:
Stable
Snowflake ARA-C01

ARA-C01: SnowPro Advanced: Architect Exam 2025 Study Guide Pdf and Test Engine

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SnowPro Advanced: Architect Certification Exam Questions and Answers

Question 1

Which Snowflake objects can be used in a data share? (Select TWO).

Options:

A.

Standard view

B.

Secure view

C.

Stored procedure

D.

External table

E.

Stream

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Question 2

An Architect has a table called leader_follower that contains a single column named JSON. The table has one row with the following structure:

{

"activities": [

{ "activityNumber": 1, "winner": 5 },

{ "activityNumber": 2, "winner": 4 }

],

"follower": {

"name": { "default": "Matt" },

"number": 4

},

"leader": {

"name": { "default": "Adam" },

"number": 5

}

}

Which query will produce the following results?

ACTIVITY_NUMBER

WINNER_NAME

1

Adam

2

Matt

Options:

A.

SELECT lf.json:activities.activityNumber AS activity_number,

IFF(

lf.json:activities.activityNumber = lf.json:leader.number,

lf.json:leader.name.default,

lf.json:follower.name.default

)::VARCHAR

FROM leader_follower lf;

B.

SELECT

C.

value:activityNumber AS activity_number,

IFF(

D.

value:winner = lf.json:leader.number,

lf.json:leader.name.default,

lf.json:follower.name.default

)::VARCHAR AS winner_name

FROM leader_follower lf,

LATERAL FLATTEN(input => json:activities) p;

E.

SELECT

F.

value:activityNumber AS activity_number,

IFF(

G.

value:winner = lf.json:leader.number,

lf.json:leader,

lf.json:follower

)::VARCHAR AS winner_name

FROM leader_follower lf,

LATERAL FLATTEN(input => json:activities) p;

Question 3

How do Snowflake databases that are created from shares differ from standard databases that are not created from shares? (Choose three.)

Options:

A.

Shared databases are read-only.

B.

Shared databases must be refreshed in order for new data to be visible.

C.

Shared databases cannot be cloned.

D.

Shared databases are not supported by Time Travel.

E.

Shared databases will have the PUBLIC or INFORMATION_SCHEMA schemas without explicitly granting these schemas to the share.

F.

Shared databases can also be created as transient databases.