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Snowflake ARA-R01 Exam With Confidence Using Practice Dumps

Exam Code:
ARA-R01
Exam Name:
SnowPro Advanced: Architect Recertification Exam
Vendor:
Questions:
162
Last Updated:
Aug 7, 2026
Exam Status:
Stable
Snowflake ARA-R01

ARA-R01: SnowPro Advanced: Architect Exam 2025 Study Guide Pdf and Test Engine

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SnowPro Advanced: Architect Recertification Exam Questions and Answers

Question 1

A healthcare company wants to share data with a medical institute. The institute is running a Standard edition of Snowflake; the healthcare company is running a Business Critical edition.

How can this data be shared?

Options:

A.

The healthcare company will need to change the institute’s Snowflake edition in the accounts panel.

B.

By default, sharing is supported from a Business Critical Snowflake edition to a Standard edition.

C.

Contact Snowflake and they will execute the share request for the healthcare company.

D.

Set the share_restriction parameter on the shared object to false.

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Question 2

A table contains five columns and it has millions of records. The cardinality distribution of the columns is shown below:

Column C4 and C5 are mostly used by SELECT queries in the GROUP BY and ORDER BY clauses. Whereas columns C1, C2 and C3 are heavily used in filter and join conditions of SELECT queries.

The Architect must design a clustering key for this table to improve the query performance.

Based on Snowflake recommendations, how should the clustering key columns be ordered while defining the multi-column clustering key?

Options:

A.

C5, C4, C2

B.

C3, C4, C5

C.

C1, C3, C2

D.

C2, C1, C3

Question 3

A table, EMP_ TBL has three records as shown:

The following variables are set for the session:

Which SELECT statements will retrieve all three records? (Select TWO).

Options:

A.

Select * FROM Stbl_ref WHERE Scol_ref IN ('Name1','Nam2','Name3');

B.

SELECT * FROM EMP_TBL WHERE identifier(Scol_ref) IN ('Namel','Name2', 'Name3');

C.

SELECT * FROM identifier WHERE NAME IN ($var1, $var2, $var3);

D.

SELECT * FROM identifier($tbl_ref) WHERE ID IN Cvarl','var2','var3');

E.

SELECT * FROM $tb1_ref WHERE $col_ref IN ($var1, Svar2, Svar3);