ARA-C01 Exam Dumps : SnowPro Advanced: Architect Certification Exam

This question tests Snowflake’s native Git integration setup pattern, which relies on Snowflake security objects to authenticate outbound access to an external Git provider. The correct sequence begins with creating an API integration because it defines and authorizes the external endpoint(s) Snowflake is allowed to communicate with. In Snowflake, integrations are the governance layer for external connectivity—administrators explicitly allow network destinations and control whether the integration is enabled, which is foundational before any credential object can be used.

Next, the Architect creates a secret to securely store the authentication material required by the Git provider (for example, a token or other supported credential). Secrets are designed for securely managing sensitive values and are referenced by other Snowflake objects without exposing the credential in plain text in SQL or configuration.

Finally, the Architect creates the Snowflake Git repository stage, which is the object that actually references the Git repo location and uses the configured integration and secret to authenticate and interact with the repository. Creating the stage last ensures all required prerequisites (allowed connectivity + stored credentials) exist and can be bound to the stage cleanly, aligning with Snowflake’s documented dependency model for external integrations.

 Option C is the correct answer because schema-on-read is a technique that allows Snowflake to ingest and consume semi-structured data without requiring a predefined schema. Snowflake supports various semi-structured data formats such as JSON, Avro, ORC, Parquet, and XML, and provides native data types (ARRAY, OBJECT, and VARIANT) for storing them. Snowflake also provides native support for querying semi-structured data using SQL and dot notation. Schema-on-read enables Snowflake to query semi-structured data at the same speed as performing relational queries while preserving the flexibility of schema-on-read. Snowflake’s near-instant elasticity rightsizes compute resources, and consumption-based pricing ensures you only pay for what you use.

Option A is incorrect because IDEF1X is a data modeling technique that defines the structure and constraints of relational data using diagrams and notations. IDEF1X is not suitable for ingesting and consuming semi-structured data, which does not have a fixed schema or structure.

Option B is incorrect because schema-on-write is a technique that requires defining a schema before loading and processing data. Schema-on-write is not efficient for ingesting and consuming semi-structured data, which may have varying or complex structures that are difficult to fit into a predefined schema. Schema-on-write also introduces additional overhead and complexity for data transformation and validation.

Option D is incorrect because information schema is a set of metadata views that provide information about the objects and privileges in a Snowflake database. Information schema is not a technique for ingesting and consuming semi-structured data, but rather a way of accessing metadata about the data.

The correct answer is B and E because they use the correct syntax and values for the identifier function and the session variables.

The identifier function allows you to use a variable or expression as an identifier (such as a table name or column name) in a SQL statement. It takes a single argument and returns it as an identifier. For example, identifier($tbl_ref) returns EMP_TBL as an identifier.

The session variables are set using the SET command and can be referenced using the $ sign. For example, $var1 returns Name1 as a value.

Option A is incorrect because it uses Stbl_ref and Scol_ref, which are not valid session variables or identifiers. They should be $tbl_ref and $col_ref instead.

Option C is incorrect because it uses identifier, which is not a valid syntax for the identifier function. It should be identifier($tbl_ref) instead.

Option D is incorrect because it uses Cvarl, var2, and var3, which are not valid session variables or values. They should be $var1, $var2, and $var3 instead. References:

Snowflake Documentation: Identifier Function

Snowflake Documentation: Session Variables

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