Selected JavaScript-Developer-I Salesforce Developer Questions Answers

Expression:

true + ' 13 ' + NaN

The + operator is left-associative, so evaluation order:

true + ' 13 '

When one operand is a string, + performs string concatenation.

true is converted to string ' true ' .

' true ' + ' 13 ' → ' true13 ' .

Result from step 1 with NaN:

' true13 ' + NaN

Again, one operand is a string, so concatenation.

NaN is converted to string ' NaN ' .

' true13 ' + ' NaN ' → ' true13NaN ' .

Final value: ' true13NaN ' .

So A is correct.

Why others are wrong:

B: ' 113NaN ' would require true to coerce to 1 first and no string to be present, which is not the case because ' 13 ' forces string concatenation.

C: 14 would require pure numeric addition, which is not the case once a string is involved.

D: ' true13 ' ignores the final + NaN part.

Concepts: type coercion with +, boolean to string, NaN to string, left-associative evaluation.

The correct answer is C .

When getAvailability(item) returns true, the code inside the if block executes:

var msg = " Username available " ;

return msg;

The variable msg receives the string value:

" Username available "

Then that same value is returned from the function.

The key point is that var is function-scoped, not block-scoped. So msg belongs to the function scope of getAvailabilityMessage(). However, because the return msg; statement is inside the same if block, the function immediately returns the assigned string when the username is available.

Option A is incorrect because msg is defined before it is returned.

Option B is incorrect because " newUserName " is not assigned or returned anywhere in the function.

Option D would only happen if getAvailability(item) returned false, because then the function would finish without an explicit return value.

For the available username scenario, the verified answer is C .

console.assert(condition, message?) logs an assertion error if condition is falsy.

To log an error when number + 2 === 0 is false, use:

console.assert(number + 2 === 0);

Other options are invalid or do not behave as described: console.error always logs, assert alone is not a built-in browser global, and console.classy doesn’t exist.

Node.js includes a built-in command-line (CLI) debugger . To use it directly in the terminal, the standard command is:

node inspect server.js

This:

Starts server.js under the Node.js inspector.

Opens the CLI debugger right in the terminal window where you ran the command.

Lets you interactively:

Step through code

Set breakpoints

Inspect variables

Continue execution, etc.

Why B is correct:

Option B (corrected to node inspect server.js) is exactly the standard Node.js command to run a script under the CLI debugger in the current terminal.

It does not rely on any external GUI tools.

You stay entirely in the terminal to debug.

Why the other options are incorrect:

A. node start inspect server.js

There is no start subcommand like this in standard Node.js CLI.

This is not a valid Node.js debugging command.

C. node server.js --inspect

This starts Node.js with the Inspector protocol enabled and is typically used to connect external tools like Chrome DevTools or VS Code.

It does not open the CLI debugger in the current terminal. Instead, it opens a debugging port that other tools attach to.

The question specifically says “only using the terminal” and “open the CLI debugger in their current terminal window”, which points to node inspect, not --inspect.

D. node -i server.js

-i starts Node in interactive REPL mode , optionally after running a script.

This is for an interactive shell, not the Node debugger.

It does not provide breakpoint/step/next/continue debugging features like the CLI debugger.

Therefore, the only option that opens the Node.js CLI debugger in the current terminal is:

Answer: B

JavaScript / Node.js knowledge / Study Guide references (concept names only, no links):

Node.js CLI debugger: node inspect < script >

Node.js inspector protocol: node --inspect

Difference between CLI debugger and DevTools-based debugging

Node.js command-line options and subcommands