CPP Exam Dumps : C++ Certified Professional Programmer

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

#include

using namespace std;

struct display {

void operator() (int i) {cout << " " << i;}

};

int main() {

int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };

vector v1(t, t + 10);

deque d1(t, t + 10);

set s1(t, t + 10);

for_each(v1.begin(), v1.end(), display); //Line I

for_each(d1.begin(), d1.end(), *(new display())); // Line II

for_each(s1.begin(), s1.end(), display()); // Line III

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3};

int t1[]={1,2,3,4};

deque d1(t, t+10);

set s1(t, t+10);

sort(d1.begin(), d1.end());

cout<<includes(s1.begin(),s1.end(), t1,t1+4)<<" "<

<

return 0;

}

Program outputs:

What will happen when you attempt to compile and run the following code? Choose all possible answers.

#include

using namespace std;

class B {};

template

class A {

T_v;

public:

A() {}

A(T v): _v(v){}

T getV() { return _v; }

void add(T a) { _v+=a; }

};

int main()

{

A a(1);

Ab;

a.add(10);

cout << a.getV() <

return 0;

}