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C++ Institute CPP Exam With Confidence Using Practice Dumps

Exam Code:
CPP
Exam Name:
C++ Certified Professional Programmer
Vendor:
Questions:
228
Last Updated:
Oct 28, 2025
Exam Status:
Stable
C++ Institute CPP

CPP: C++ Certified Professional Programmer Exam 2025 Study Guide Pdf and Test Engine

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C++ Certified Professional Programmer Questions and Answers

Question 1

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

#include

using namespace std;

struct display {

void operator() (int i) {cout << " " << i;}

};

int main() {

int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };

vector v1(t, t + 10);

deque d1(t, t + 10);

set s1(t, t + 10);

for_each(v1.begin(), v1.end(), display); //Line I

for_each(d1.begin(), d1.end(), *(new display())); // Line II

for_each(s1.begin(), s1.end(), display()); // Line III

return 0;

}

Options:

A.

program outputs: 10 5 9 6 2 4 7 8 3 1 10 5 9 6 2 4 7 8 3 1 1 2 3 4 5 6 7 8 9 10

B.

program outputs: 10 5 9 6 2 4 7 8 3 1 10 5 9 6 2 4 7 8 3 1 10 5 9 6 2 4 7 8 3 1

C.

compilation error in line I

D.

compilation error in line II

E.

compilation error in line III

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Question 2

What will happen when you attempt to compile and run the code below, assuming you enter the following sequence: 1 2 3?

#include

using namespace std;

int main ()

{

int a,b,c;

cin>>a>>b>>c;

cout<<a<

return 0;

}

Program will output:

Options:

A.

123

B.

1 2 3

C.

321

D.

compilation error

E.

the result is unspecified

Question 3

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

class B { int val;

public:

B(int v=0):val(v){}

int getV() const {return val;}

operator int () const { return val;} };

ostream & operator <<(ostream & out, const B & v) { out<

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

B t[]={3,2,4,1,5,6,10,8,7,9};

vector v1(t, t+10);

transform(v1.begin(), v1.end(), v1.begin(), bind2nd(plus(), 1));

for_each(v1.rbegin(), v1.rend(), Out(cout));cout<<endl;

return 0;

}

Program outputs:

Options:

A.

3 2 4 1 5 6 10 8 7 9

B.

4 3 5 2 6 7 11 9 8 10

C.

9 7 8 10 6 5 1 4 2 3

D.

10 8 9 11 7 6 2 5 3 4

E.

compilation error