CAP Exam Dumps : Certified AppSec Practitioner Exam

The request is a POST to /dashboard/userdata with a parameter The response is a 200 OK with an HTML page titled "Admin Panel," suggesting the server processed the request and returned content from Let’s evaluate the vulnerability:

Analysis: The useragent parameter contains a URL and the server appears to fetch content from this URL, as indicated by the response containing the "Admin Panel" page. The URL 127.0.0.1 refers to the server’s localhost, meaning the server is making an internal request to itself based on user input. This is a hallmark of Server-Side Request Forgery (SSRF), where an attacker can trick the server into making requests to arbitrary locations, including internal systems (e.g., 127.0.0.1) or external sites. SSRF can lead to accessing internal resources (e.g., admin panels, metadata endpoints) or performing unauthorized actions.

Option A ("HTTP Desync Attack"): HTTP Desync attacks exploit discrepancies in how front-end and back-end servers interpret HTTP requests (e.g., smuggling requests). This scenario involves a straightforward POST request with no evidence of desynchronization or smuggling, so this is incorrect.

Option B ("File Path Traversal Attack"): File Path Traversal involves manipulating file paths (e.g., ../../etc/passwd) to access unauthorized files on the server’s filesystem. The useragent parameter contains a URL, not a file path, and the response indicates a web request, not filesystem access, so this is incorrect.

Option C ("Open URL Redirection"): Open URL Redirection occurs when the server redirects the client to a user-supplied URL (e.g., via a Location header). The response here is a 200 OK, not a redirect (e.g., 302 Found), and the server is fetching content server-side, not redirecting the client, so this is incorrect.

Option D ("Server-Side Request Forgery"): Correct, as the server is making a request to based on the useragent parameter, indicating an SSRF vulnerability.

The correct answer is D, aligning with the CAP syllabus under "Server-Side Request Forgery (SSRF)" and "OWASP Top 10 (A10:2021 - Server-Side Request Forgery)."References: SecOps Group CAP Documents - "SSRF Vulnerabilities," "Input Validation for URLs," and "OWASP SSRF Prevention Cheat Sheet" sections.

Cross-Site Request Forgery (CSRF) occurs when an attacker tricks a user’s browser into making an unintended request to a site where the user is authenticated, potentially performing actions like changing a password. Let’s analyze the request:

The request is a POST to /changepassword with a Cookie: JSESSIONID, indicating the user is authenticated via a session. The Content-Length: 95 and payload (new_password=lov3MyPiano23&confirm_password=lov3MyPiano23) suggest a state-changing operation (password change).

CSRF vulnerability arises when the request lacks a unique, unpredictable token to validate its legitimacy, and the server accepts it based solely on the session cookie. The request includes no CSRF token (e.g., in the body or headers like X-CSRF-Token).

The Sec-Fetch-Site: same-origin header indicates the request originates from the samedomain, but this is a browser feature and does not guarantee server-side protection against CSRF from a malicious site (e.g., via a hidden iframe or form submission).

Without a CSRF token, an attacker could craft a malicious HTML page with a form that submits this exact request when a victim visits their site while authenticated to example.com, exploiting the browser’s automatic inclusion of the JSESSIONID cookie. This is a textbook CSRF vulnerability.

Option A ("True"): Correct, as the request lacks a CSRF token, making it vulnerable to CSRF attacks.

Option B ("False"): Incorrect, as the absence of a CSRF token indicates vulnerability.

The correct answer is A, aligning with the CAP syllabus under "Cross-Site Request Forgery (CSRF)" and "Session Management."References: SecOps Group CAP Documents - "CSRF Prevention," "Session Security," and "OWASP CSRF Prevention Cheat Sheet" sections.

Symmetric key encryption algorithms use the same key for both encryption and decryption, while asymmetric algorithms use a pair of keys (public and private). Let’s evaluate the options:

Option A ("RC4"): RC4 is a symmetric key encryption algorithm. It is a stream cipher that uses a single key to both encrypt and decrypt data, though it is considered insecure due to known cryptographic weaknesses (e.g., biases in the keystream).

Option B ("AES"): AES (Advanced Encryption Standard) is a symmetric key encryption algorithm. It uses a single key (e.g., 128, 192, or 256 bits) for both encryption and decryption, widely regarded as secure when properly implemented.

Option C ("DES"): DES (Data Encryption Standard) is a symmetric key encryption algorithm. It uses a 56-bit key for both encryption and decryption, but it is now considered insecure due to its small key size and vulnerability to brute-force attacks.

Option D ("RSA"): RSA (Rivest-Shamir-Adleman) is an asymmetric key encryption algorithm. It uses a public key to encrypt and a private key to decrypt, making it an asymmetric algorithm, not a symmetric one.

The correct answer is D, as RSA is the only asymmetric algorithm listed, aligning with the CAP syllabus under "Cryptography Fundamentals" and "Symmetric vs. Asymmetric Encryption."References: SecOps Group CAP Documents - "Symmetric Encryption Algorithms," "Asymmetric Encryption," and "OWASP Cryptographic Storage Cheat Sheet" sections.