To determine the correct result of the query, a Data Analyst must evaluate the nested functions according to standard SQL order of operations while correctly identifying how Snowflake handles NULL values in aggregate calculations.
Step 1: Evaluating AVG(GRADE)
The AVG() function calculates the arithmetic mean of the non-null values in a column. Based on the provided table data, the grades are: 4, 1, 2, 1, and 2. The sixth row contains a NULL grade. In Snowflake, as per ANSI SQL standards, aggregate functions ignore NULL values entirely. They are not treated as zeros, nor do they cause the function to return NULL (unless the entire column is null).
Sum of non-null values: $4 + 1 + 2 + 1 + 2 = 10$
Count of non-null values: $5$
Result: $10 / 5 = 2.0$
Step 2: Evaluating CEIL(..., 2)
The CEIL (or CEILING) function is typically used to return the smallest integer value that is greater than or equal to the input. However, Snowflake's CEIL function also supports an optional second argument for scale (precision).
The input is the result from the previous step: 2.0.
The scale argument is 2.
The function CEIL(2.0, 2) attempts to round the value up to the nearest value with two decimal places. Since 2.0 is already a whole number and has no fractional component beyond the specified scale, the ceiling remains 2.0.
Evaluating the Options:
Option A is incorrect as it represents a massive scaling error.
Option C and D are incorrect because they result from mathematical errors or incorrectly including the NULL row in the denominator (e.g., $10 / 6 = 1.66$, then rounded up).
Option B is the 100% correct answer. It accurately reflects the result of the AVG function ($2.0$) followed by the CEIL operation, which preserves the value as it is already at the target ceiling. This question tests precision in both mathematical logic and the technical nuances of Snowflake-specific SQL functions.