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Pegasystems PEGAPCLSA86V2 Exam With Confidence Using Practice Dumps

Exam Code:
PEGAPCLSA86V2
Exam Name:
Lead System Architect (LSA) Pega Architecture Exam 86V2
Certification:
Certified Lead System Architect (CLSA)
Vendor:
Pegasystems
Questions:
148
Last Updated:
Jul 4, 2026
Exam Status:
Stable
Pegasystems PEGAPCLSA86V2

PEGAPCLSA86V2: Certified Lead System Architect (CLSA) Exam 2025 Study Guide Pdf and Test Engine

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Lead System Architect (LSA) Pega Architecture Exam 86V2 Questions and Answers

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Question 1

You need to define a new LDAP authentication servlet because all of the standard LDAP servlets are

being used in authentication services

which two task do you perform to implement this requirement

Options:

A.

Copy an existing LDAP servlet and rename it

B.

Create a new mapping servlet and URL pattern

C.

add a new URL pattern to the existing mapping servlet

D.

rename an existing LDAP servlet

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Question 2

The following figure depicts a hierarchy of applications that are built on other applications.

Specifically , the productionapp application is built on applications customerapp and

employeeapp. Each of these applications has additional built-on applications, including the duplicated MYEnterpriseApp application, which has two different versions in use. All applications are built on the same version of PegaRUUS.

Options:

Question 3

A pega application has cases that represent customer accounts each with many members.

When a member of a customer account registers with the application through an offline

component, a related registration transaction is recorded. An advanced agent updates the

customer account cases with new members. The application is running in a multimode

system and advanced agents are enabled on all nodes. Which two elements are valid design

choices? (choose two)

Options:

A.

Use the optimistic locking option on the case types.

B.

Create a Registration subcase configured to run in offline mode.

C.

Leverage the default object lock contention requeuing capability.

D.

Override DetermineLockString to use .AccountID instead of .pyID as the lock string.

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