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C++ Institute CPP Exam With Confidence Using Practice Dumps

Exam Code:
CPP
Exam Name:
C++ Certified Professional Programmer
Vendor:
Questions:
228
Last Updated:
Apr 30, 2025
Exam Status:
Stable
C++ Institute CPP

CPP: C++ Certified Professional Programmer Exam 2025 Study Guide Pdf and Test Engine

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C++ Certified Professional Programmer Questions and Answers

Question 1

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

class A {

int a;

public:

A(int a) : a(a) {}

int getA() const { return a; } void setA(int a) { this?>a = a; }

};

struct Even {

bool operator ()(const A & a, const A &b) {

return (a.getA() % 2)==b.getA() % 2;

}

};

int main () {

int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};

deque d (t,t+15);

deque::iterator it = search_n(d.begin(), d.end(), 3, 2, Even());

cout<< it?d.begin()<

return 0;

}

Program outputs:

Options:

A.

compilation error

B.

12

C.

3

D.

1

E.

15

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Question 2

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t1[]={3,2,4,1,5};

int t2[]={6,10,8,7,9};

vector v1(5);

transform(t1,t1+5,t2,v1.rbegin(), plus());

for_each(v1.rbegin(), v1.rend(), Out(cout));cout<<endl;

return 0;

}

Program outputs:

Options:

A.

9 12 12 8 14

B.

14 8 12 12 9

C.

3 2 4 1 5 6 10 8 7 9

D.

1 2 3 4 5 6 7 8 9 10

E.

compilation error

Question 3

What will happen when you attempt to compile and run the following code?

#include

#include

#include

#include

#include

using namespace std;

int main() {

int t[] = { 3, 4, 2, 1, 0, 3, 4, 1, 2, 0 };

vector v(t, t + 10);

multimap m;

for (vector::iterator i = v.begin(); i != v.end(); i++) {

stringstream s;s << *i << *i;

m.insert(pair(*i, s.str()));

}

pair::iterator, multimap::iterator> range;

range = m.equal_range(2);

for (multimap::iterator i = range.first; i != range.second; i++) {

cout << i?>first << " ";

}

return 0;

}

The output will be:

Options:

A.

2 2

B.

1 2

C.

1 3

D.

2

E.

0 2