CPIM-8.0 Premium Exam Questions

Given the bill of material (BOM) information, we can calculate the weekly gross requirement of component F by considering the independent requirements of Component A and B. For Component A, there is no direct requirement for Component F. For Component B, which has an independent requirement of 20 pcs per week, each requires 4 pcs of Component F according to its BOM. So, the total weekly gross requirement for Component F due to Component B is 204 = 80 pcs. Additionally, each piece of Component A requires 2 pieces of Component C according to its BOM and has an independent requirement of 10 pcs per week; hence requiring a total of 20 pieces of component C per week. Each piece of component C in turn requires 4 pieces of component F according to its BOM; hence requiring a total weekly gross requirement for component F due to component A is: 204 =80 pcs. Adding both gives us a total weekly gross requirement for component F as:80+80=160pcs. References:

•CPIM Part 1 Learning System, Module 4: Inventory Management, Section 4.2: Inventory Management Policies and Objectives

•CPIM Part 2 Learning System, Module 1: Supply Chain Strategy, Section 1.3: Capacity Management