5V0-22.23 Exam Dumps : VMware vSAN Specialist v2

To ensure that a single rack failure is not going to affect the data availability, while minimizing the number of racks used, the administrator has to do the following:

• Distribute servers across at least three different racks. This is because vSAN supports up to three fault domains per cluster, which can be used to tolerate one or two failures. If only two racks are used, then only one failure can be tolerated4
• Configure three fault domains. A fault domain is a logical grouping of hosts that share a common failure point, such as a rack or a power supply. By configuring fault domains, vSAN can place replicas of an object across different fault domains, so that a failure within one fault domain does not result in data loss orunavailability4 References: 4: VMware vSAN Specialist v2 Exam Preparation Guide, page 13

To expand disk group #2 to have three capacity devices, the vSAN administrator should add the new capacity device to the disk group and vSAN will automatically rebalance. This action allows the administrator to increase the storage capacity of the disk group without disrupting any ongoing operations or evacuating any data. vSAN will automatically distribute data across all devices in the disk group to balance performance and utilization. The other options are not correct. Creating a new disk group with a single capacity device and then migrating the existing capacity devices is not necessary, as it would require more steps and resources than adding a device to an existing disk group. Putting the entire ESXi host or the disk group in maintenance mode and evacuating all data is not required, as it would cause downtime and data movement that could be avoided by adding a device to an existing disk group. References: Add Devices to the Disk Group; Expanding a vSAN Cluster

To protect a virtual machine against a disk or disk group failure, the storage policy must have a failure tolerance method (FTM) of RAID-1 or RAID-6 and a failure to tolerate (FTT) value of at least 1. RAID-1 mirrors the data across multiple disk groups, while RAID-6 uses erasure coding to stripe the data and parity information across multiple disk groups. RAID-5 is not suitable for this scenario, as it can only tolerate one disk failure per stripe. FTT 2 or 3 would require more disk groups than available in the cluster. Therefore, the correct options are C and E. References: 1, page 8; 2, section 3.1