CIMA F3 Exam With Confidence Using Practice Dumps

In CIMA F3’s coverage of short-term financing, commercial paper (CP) is identified as a very cost-effective funding source for large, high-credit-quality companies. CP is an unsecured, short-term promissory note, typically issued for periods up to 270 days, making it ideal for a 6-month funding need. Because it is issued directly into the money markets by strong credits, the interest cost is usually lower than overdrafts or short-term bank loans, which include a bank’s margin.

The scenario states that the company is large, listed, has an “excellent credit rating”, minimal default risk and already has a commercial paper programme. This matches the textbook profile of a company for which CP is the cheapest source of short-term borrowing.

Treasury bills (C) are issued by governments, not companies, so they are an investment vehicle, not a borrowing method here. Bank overdrafts (A) are flexible but generally expensive and better for fluctuating day-to-day needs. A 6-month term loan (B) tends to involve higher arrangement fees and interest margins than CP. Therefore, option D is the most cost-effective choice.

A – Access to technical expertise: Q’s staff are leading experts and human capital is very valuable; acquiring this is a clear benefit.

D – Gain economies of scale: Both firms operate in the same technical service industry, so combining operations can reduce average costs and share overheads.

E – Improve EPS: Q has shown consistent earnings growth; if acquired at a reasonable price, this growth can enhance M’s earnings and potentially its EPS.

Diversification benefits (B) are limited because they are in the same industry, and intangible assets such as human capital are not strong collateral for borrowing (C).

Cash flows:

Years 1–3: 100, 100, 100

From year 4: grow at 2% forever. Cost of capital = 12%.

PV of years 1–3:

PV1−3=1001.12+1001.122+1001.123≈240\text{PV}_{1-3} = \frac{100}{1.12} + \frac{100}{1.12^2} + \frac{100}{1.12^3} \approx 240PV1−3​=1.12100​+1.122100​+1.123100​≈240

Terminal value at end of year 3:

Year 4 CF = 100×1.02=102100 \times 1.02 = 102100×1.02=102

TV3=1020.12−0.02=1020.10=1,020\text{TV}_3 = \frac{102}{0.12 - 0.02} = \frac{102}{0.10} = 1{,}020TV3​=0.12−0.02102​=0.10102​=1,020

PV of terminal value:

PV(TV)=1,0201.123≈726\text{PV(TV)} = \frac{1{,}020}{1.12^3} \approx 726PV(TV)=1.1231,020​≈726

Total value ≈ 240+726=966240 + 726 = 966240+726=966.

So the value is $966 million → Option A.