WGU Scripting-and-Programming-Foundations Exam With Confidence Using Practice Dumps

 Dijkstra’s shortest path algorithm is designed to find the shortest path between nodes in a graph. This can be applied to various scenarios, such as routing problems, network optimization, and in this case, determining the most fuel-efficient flight plan. The algorithm works by iteratively selecting the unvisited vertex with the smallest tentative distance from the source, then visiting the neighbors of this vertex and updating their tentative distances if a shorter path is found. This process continues until the destination vertex is reached or all reachable vertices have been visited.

In the context of the given options, Dijkstra’s algorithm is best suited for option B, where the goal is to find the most fuel-efficient path (i.e., the shortest path) between multiple points (coordinates of five positions). The algorithm is not designed to solve problems like searching for an element in an array (option A), finding the longest common subsequence (option C), or searching for a name in a list (option D).

Interpreted languages are designed to be executed one statement at a time by an interpreter. This allows for immediate execution and feedback, which is useful for debugging and interactive use. Unlike compiled languages, interpreted languages do not generate machine code prior to execution, and they do not produce syntax errors during compilation because there is no compilation step. They are not restricted to one machine, as the interpreter can be implemented on various systems, and they do not require the programmer to write machine code.

The pseudocode provided appears to be a loop that calculates the sum of numbers. Without seeing the exact pseudocode, I can deduce based on common programming patterns that if the loop is designed to add numbers from 1 to 5, the sum would be 1 + 2 + 3 + 4 + 5, which equals 15. This is a typical example of a series where the sum of the first n natural numbers is given by the formula

2n(n+1)​

, and in this case, with n being 5, the sum is

25(5+1)​=15