H12-831_V1.0 Exam Dumps : HCIP-Datacom-Advanced Routing & Switching Technology V1.0

Comprehensive and Detailed In-Depth Explanation:

Understanding Port Isolation in the Network

Network Setup Details:

The switch is Layer 3, with VLANIF10 configured as 10.1.1.1/24 (gateway for all PCs).

All PCs are in VLAN 10 and use 10.1.1.1 as the default gateway.

Port isolation is enabled on switch interfaces, dividing them into two groups:

Group 1 (PC1 & PC2): GigabitEthernet0/0/1 and GigabitEthernet0/0/2

Group 2 (PC3 & PC4): GigabitEthernet0/0/3 and GigabitEthernet0/0/4

Port Isolation Behavior:

Ports within the same isolation group CAN communicate with each other.

Ports from different isolation groups CANNOT communicate directly.

All devices CAN still communicate with the L3 switch (10.1.1.1), which acts as the gateway.

Ping Analysis from PC1 (10.1.1.2)

Destination IP

Device

Connected Port

Isolation Group

Ping Result from PC1

10.1.1.3

PC2

GigabitEthernet0/0/2

Group 1

✅ Can Ping

10.1.1.4

PC3

GigabitEthernet0/0/3

Group 2

❌ Cannot Ping

10.1.1.5

PC4

GigabitEthernet0/0/4

Group 2

❌ Cannot Ping

10.1.1.1

L3 Switch (Gateway)

N/A

Not Isolated

✅ Can Ping

Which IPs Cannot be Pinged from PC1?

PC3 (10.1.1.4) and PC4 (10.1.1.5) are in a different isolation group (Group 2), so PC1 cannot reach them directly.

PC2 (10.1.1.3) is in the same isolation group (Group 1), so PC1 can ping it.

PC1 can ping the gateway (10.1.1.1) because the switch is Layer 3 and forwards traffic.

Thus, the correct answers are: A. 10.1.1.3 and D. 10.1.1.4.

Final Conclusion:

✅ PC1 CAN ping:

10.1.1.3 (PC2, same isolation group)

10.1.1.1 (Gateway, L3 Switch)

❌ PC1 CANNOT ping:

10.1.1.4 (PC3, different isolation group)

10.1.1.5 (PC4, different isolation group)

Thus, the correct answer is: A. 10.1.1.3 and D. 10.1.1.4.

Comprehensive and Detailed In-Depth Explanation:

Understanding the OSPF Network Structure in the Question:

OSPF Areas & Routers:

Area 3: Contains R5 (which has loopback 10.0.5.5/32).

Area 1: Contains R6.

Area 2: Contains R4.

Area 0 (Backbone Area): Contains R1, R2, and R3 (which interconnect the other areas).

ACL 2000 Filtering Rule:

The ACL rule 2000 explicitly denies 10.0.5.5/32 from being imported.

The filter 2000 import command applies this filter to Area 0, preventing routes from Area 3 (including R5's loopback) from being learned by Area 0 routers (R1, R2, and R3).

Route Distribution Analysis:

R5 (Area 3):

R5 has 10.0.5.5/32 configured on its Loopback0.

Since OSPF is enabled, R5 advertises the route to R6 in Area 1.

R6 (Area 1) → R2 (Area 0, Backbone Router):

Without filtering, R6 would normally propagate 10.0.5.5/32 to R2 (since R2 is a backbone router in Area 0).

However, since ACL 2000 is applied in Area 0, R2 blocks this route from being imported.

Therefore, R2 does not learn 10.0.5.5/32.

R2 → R1 and R3 (Both in Area 0):

R2 would typically share any learned routes with R1 and R3 in Area 0.

But since R2 itself does not have 10.0.5.5/32, neither R1 nor R3 can receive it.

Thus, R1 and R3 also do not have 10.0.5.5/32 in their routing tables.

R4 (Area 2) is Unaffected:

Since R4 is in Area 2, it is not directly impacted by the filter applied in Area 0.

It can still receive the route via another path if redistribution is configured properly.

Final Conclusion:

R1, R2, and R3 do not have the 10.0.5.5/32 route due to the filter 2000 import command applied in Area 0.

R4 may still have the route since it is not affected by the filtering in Area 0.

Thus, the correct answer is:✅ R1, R3, R2 do not have the route 10.0.5.5/32 in their routing tables.