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Oracle 1z0-883 Exam With Confidence Using Practice Dumps

Exam Code:
1z0-883
Exam Name:
MySQL 5.6 Database Administrator
Certification:
Oracle Other Certification
Vendor:
Oracle
Questions:
100
Last Updated:
Jun 30, 2025
Exam Status:
Stable
Oracle 1z0-883

1z0-883: Oracle Other Certification Exam 2025 Study Guide Pdf and Test Engine

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MySQL 5.6 Database Administrator Questions and Answers

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Question 1

Consider the query:

Mysql> SET @run = 15;

Mysql> EXPLAIN SELECT objective, stage, COUNT (stage)

FROM iteminformation

WHERE run=@run AND objective=’7.1’

GROUP BY objective,stage

ORDER BY stage;

The iteminformation table has the following indexes;

Mysql> SHOW INDEXES FROM iteminformation:

This query is run several times in an application with different values in the WHERE clause in a growing data set.

What is the primary improvement that can be made for this scenario?

Options:

A.

Execute the run_2 index because it has caused a conflict in the choice of key for this query.

B.

Drop the run_2 index because it has caused a conflict in the choice of key for this query.

C.

Do not pass a user variable in the WHERE clause because it limits the ability of the optimizer to use indexes.

D.

Add an index on the objective column so that is can be used in both the WHERE and GROUP BY operations.

E.

Add a composite index on (run,objective,stage) to allow the query to fully utilize an index.

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Question 2

You are creating a new server with the same accounts as an existing server. You do this by importing a mysqldump file of the mysql database.

You test whether the import was successful by using the following commands:

Mysql> select user, host, password from mysql.user;

9 rows in set (0.00 sec)

Mysql> show grants for ‘admin’@’%’;

ERROR 1141 (42000): There is no such grant defined for user ‘admin’ on host ‘%’

Which command will fix this issue?

Options:

A.

CREATE USER ‘admin’ @’%’;

B.

GRANT USAGE ON *.* TO ‘admin’@’%’;

C.

FLUSH PRIVILEGES;

D.

FLUSH HOST CACHE;

E.

UPDATE mysql.user SET Create_user_priv = ‘Y’ WHERE user= ‘admin’;

Question 3

The validate_password plugin is loaded and displays the following settings in global variables:

Mysql> SHOW VARIABLES LIKE ‘validate_password%’;

When attempting to set your password, you get the following error:

Mysql> SET PASSWORD = PASSWORD (‘Hoverl@%’);

ERROR 1819 (HY000): Your password does not satisfy the current policy requirements

What is the cause of the error?

Options:

A.

The password is eight characters long, but needs to exceed validate_password_length to be valid.

B.

All of the MEDIUM password policy requirements have not been honored.

C.

The password matches a substring Hover as a dictionary word.

D.

The password does not match the validate_passoword_number_count requirement.

E.

There is no dictionary file defined, so password validation cannot work as expected.

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